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  4. The ionic radii of Ca2+ and F- are 100 pm and 133 pm respectively. The coordination number of Ca2+ in the ionic solid will be

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Q. The ionic radii of $ C{{a}^{2+}} $ and $ {{F}^{-}} $ are 100 pm and 133 pm respectively. The coordination number of $ C{{a}^{2+}} $ in the ionic solid will be

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Solution:

Radius $ ratio=\frac{{{r}_{C{{a}^{2+}}}}}{{{r}^{F-}}}=\frac{100pm}{133pm}=0.75 $ As, $ \text{0}\text{.73}\,\text{}\frac{{{\text{r}}_{\text{cation}}}}{{{\text{r}}_{\text{anion}}}}. $ So, coordination number of cation = 8