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Q. The ionic radii ($\mathring{A}$) of $C^{4-}$ and $O^{2-}$ respectively are 2.60 and 1.40. The ionic radius of the isoelectronic ion $N^{3-}$ would be

Classification of Elements and Periodicity in Properties

Solution:

The ionic radii of isoelectronic ions decrease with the increase in the magnitude of the nuclear charge.
So, decreasing order of ionic radii is $C^{(4-)} gt N^{(3-)} gt O^{(2-)}$