Question

The ionic radii $N^{3-}, O^{2-}, F^{-}$and $N a^{+}$follow the order

• A. $N^{3-}>O^{2-}>F^{-}>N a^{+}$
• B. $Na ^{3-}> Na ^{+}> O ^{2-}> F ^{-}$
• C. $N a^{+}>O^{2-}>N a^{3-}>F^{-}$
• D. $O^{2-}>F^{-}>N a^{+}>N a^{3-}$

Answer 1

Answer: (A)

$\Rightarrow $ Cations has lower atomic radius that the isolated atom Whereas anions has higher atomic radius than the isolated
$\Rightarrow $ Higher the positive charge, lesser is the atomic radius and higher the negative charge, greater is the atonic radius. So, the increasing order of ionic radii is:-
$N ^{3-}> O ^{2-}> f ^{-}> Na ^{+}$