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Q. The intrinsic number density of charge carriers in a semiconductor is $2.5\times10^{13}cm^{-3}$,It is doped with donor atoms of number density $1.25\times10^{17}cm^{-3}$, the ratio of conductivities of doped and intrinsic semiconductors is

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

$n_{e}=2.5 \times 10^{13} / cm ^{3}$
$n_{d}=1.25 \times 10^{17} / cm ^{3}$
$\frac{\sigma_{d}}{\sigma_{e}}=?$
$\sigma \alpha \,n_{e}$
$\sigma=\frac{1}{\rho}=n_{e} \mu_{e} \cdot e$
$\frac{\sigma_{d}}{\sigma_{e}}=\frac{n_{d}}{n_{e}}=\frac{1.25 \times 10^{17}}{2.5 \times 10^{13}}$
$\frac{\sigma_{d}}{\sigma_{e}}=5000$