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  4. The interval in which y=x2 e-x is increasing is

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Q. The interval in which $y=x^{2} e^{-x}$ is increasing is

Solution:

$f^{1}(x)>0 \Rightarrow x^{2} \cdot e^{-x} \cdot(-1)+e^{-x} \cdot 2 x>0$