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Q. The intensity of electric field required to balance a proton of mass $1.7 \times 10^{-27} kg$ and charge $1.6 \times 10^{-19} C$ is nearly

Electric Charges and Fields

Solution:

Since $q E=m g$
$ \Rightarrow E=\frac{m g}{q}=\frac{1.7 \times 10^{-27} \times 9.8}{1.6 \times 10^{-19}}$
$=10.0 \times 10^{-8}=1 \times 10^{-7} V / m$