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Q. The innermost orbit of the hydrogen atom has a diameter of $1.06 \,\mathring{A}$. What is the diameter (in $\mathring{A}$ ) of the tenth orbit?

Atoms

Solution:

As $r_{n} \equiv n^{2}$
$\Rightarrow \frac{r_{1}}{r_{10}}=\left(\frac{1}{10}\right)^{2}$
$ \Rightarrow r_{10}=100 \times 1.06=106 \,\mathring{A}$