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Q. The inertia for electric circuit is (symbols have their usual meanings)

Solution:

$E = \frac{1}{2}kx^{2}+\frac{1}{2}mv^{2}\left(for \,mechanical\, system\right)$
$U\, =\, 1 \,q + \, \frac{1}{2}Li^2$ (for electrical system)
Hence L is called as inertia of electrical circuit.