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Q. The increasing order of $PK_{b}$ for the following compounds will be

$\left(\right.1\left.\right)$ $NH_{2}-CH=NH,$

$\left(\right.2\left.\right)$ Question

$\left(\right.3\left.\right)$ $CH_{3}NHCH_{3}$

NTA AbhyasNTA Abhyas 2020Organic Chemistry – Some Basic Principles and Techniques

Solution:

$pK_{b} \propto \frac{1}{K_{b}} \propto \frac{1}{B a s i c \, s t r e n g t h}$

As basic nature decreases in the order (2) > (1) > (3). So $pK_{b}$ order is as follows

$\left(\right.2\left.\right) < \left(\right.1\left.\right) < \left(\right.3\left.\right)$