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Q. The increase in boiling point of a solution containing 0.6 g urea in 200 gram water is 0.50$^\circ$C.Find the molal elevation constant

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Solution:

Molality, $m = \frac{0.6}{60} \times \frac{1000}{200} $ = 0.05 m
$\Delta \, T_b $ = 0.5 K
now $\Delta \, T_b = K_b \times m$
or $K_b = \frac{\Delta \, T_b}{m} = \frac{0.5}{0.05}$ = 10 K kg mol$^{-1}$