1. Tardigrade
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  3. Chemistry
  4. The hydrogen electrode is dipped in a solution of pH = 3 at 25°C. The potential of the cell would be (the value of 2.303 RT/F is 0.059 V)

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Q. The hydrogen electrode is dipped in a solution of $pH = 3$ at $25^\circ$C. The potential of the cell would be (the value of $2.303 \,RT/F$ is $0.059 \,V)$

Electrochemistry

Solution:

$pH = 3$
$\therefore [H^+] = 10^{-3}$
$\therefore [H^+] + e^- \rightarrow \frac{1}{2} H_2$
$E = E^0 - \frac{0.059}{n} \,log \frac{1}{[H^+]} $
$= 0 - \frac{0.059}{1} \,log \,10^3$
$E = - 0.177\,V$