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Chemistry
The hydrated salt Na 2 CO 3 ⋅ xH 2 O undergoes 63 % loss in mass on heating and becomes anhydrous. The value of x is
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Q. The hydrated salt $Na _{2} CO _{3} \cdot xH _{2} O$ undergoes $63 \%$ loss in mass on heating and becomes anhydrous. The value of $x$ is
Some Basic Concepts of Chemistry
A
3
18%
B
5
21%
C
7
23%
D
10
38%
Solution:
The loss in mass is due to elimination of water of
crystallisation of $Na _{2} CO _{3} \cdot xH _{2} O$
Hence, $\frac{18 x \times 100}{106+18 x}=63$
$ \Rightarrow x=10$