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Q. The hydrated salt $Na _{2} CO _{3} \cdot xH _{2} O$ undergoes $63 \%$ loss in mass on heating and becomes anhydrous. The value of $x$ is

Some Basic Concepts of Chemistry

Solution:

The loss in mass is due to elimination of water of

crystallisation of $Na _{2} CO _{3} \cdot xH _{2} O$

Hence, $\frac{18 x \times 100}{106+18 x}=63$

$ \Rightarrow x=10$