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  4. The hybridization state of carbon atoms in the product formed by the reaction of ethyl chloride with aqueous KOH is:

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Q. The hybridization state of carbon atoms in the product formed by the reaction of ethyl chloride with aqueous KOH is:

EAMCETEAMCET 1997

Solution:

The function of aqueous KOH is to convert halogen to hydroxy group. So, ethyl chloride reacts with aq. KOH to give $ {{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH} $ as: $ \begin{matrix} {{C}_{2}}{{H}_{5}} \\ \underset{Aq.}{\mathop{O\overset{+}{\mathop{H}}\,}}\, \\ \end{matrix}\xrightarrow{{}}\underset{\text{Ethyl}\,\text{alcohol}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,+KCl $ In $ {{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH} $ all the four valencies of carbon are single bonded. So, hybridization of carbon atom in $ {{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH} $ is $ \text{s}{{\text{p}}^{3}}. $