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Q.
The hybridisation states of $ [Ni(CO)_4] $ , $ [Ni(CN)_4]^{2-} $ and $ [NiCl_4]^{2-} $ species are respectively
AMUAMU 2011Coordination Compounds
Solution:
In the formation of $[Ni(CO)_4]$, oxidation state of $Ni$ is $O$ and its electronic
configuration is $[Ar] \,3d^8\,4s^2$.
Hence, we have
In $[Ni(CN)_4]^{2-}$, $Ni$ is in $+2$ oxidation state and $CN^-$ is a strong ligand and as it approaches the metal ion, the electrons must pair up.
In $[NiCl_4]^{2-}, Cl^-$ provides a weak field ligand. It is therefore, unable to pair up the unpaired electrons of the $3d$ orbitals.