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  4. The hybrid orbitals used by bromine atom in BrF3 are

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Q. The hybrid orbitals used by bromine atom in $BrF_3$ are

Chemical Bonding and Molecular Structure

Solution:

$BrF_3$.
Total $ \,e^- = 7 + 7 \times 3 = 28$
$= 8 \times 3 + 4$
no. of hybridised orbitals $ = \frac{8 \times 3}{8} + \frac{4}{2} $
$ = 3 + 2 = 5 $
$\therefore sp^3d$ hybridization