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Q. The horizontal range is four times the maximum height attained by a projectile. The angle of projection is

KEAMKEAM 2012Motion in a Plane

Solution:

Given $H = 4R $
$\therefore \:\:\: \frac{u^2 \, \sin \, 2 \theta}{g} = 4 \times \frac{u^2 \, sin^2 \theta}{2g}$
or $\tan \, \theta = 1$ or $\theta = 45^\circ$