1. Tardigrade
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  4. The horizontal component of the earth's magnetic field at a place is 3 × 10-4 T and the dip is tan -1((4/3)) . A metal rod of length 0.25 m placed in the north-south position and is moved at a constant speed of 10 cm / s towards the east. The emf induced in the rod will be

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Q. The horizontal component of the earth's magnetic field at a place is $3 \times 10^{-4} T$ and the dip is $\tan ^{-1}\left(\frac{4}{3}\right) .$ A metal rod of length $0.25\, m$ placed in the north-south position and is moved at a constant speed of $10\, cm / s$ towards the east. The emf induced in the rod will be

Electromagnetic Induction

Solution:

Rod is moving towards east, so induced emf across its end will be
$e=B_{V} v l=\left(B_{H} \tan \delta\right) v l$
$\therefore e=3 \times 10^{-4} \times \frac{4}{3} \times\left(10 \times 10^{-2}\right) \times 0.25$
$=10^{-5} V =10\, \mu V$