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Q.
The highest oxidation state exhibited by transition metals is
J & K CETJ & K CET 2008The d-and f-Block Elements
Solution:
Maximum oxidation state of transition metals = number of electrons in $(n-1) d$
orbital + number of electrons in $n s$ orbital.
The electronic configuration of
$O S=[X e] 4 f^{14}, 5 d^{6}, 6 s^{2}$
$\therefore $ Maximum oxidation state $=6+2=8$
$\therefore $ The highest oxidation state exhibited by transition metal is
$+8 eg , OsO _{4}$.