Question

The Henry law constant for dissolution of a gas in aqueous medium is $3\times 10^{2}atm$ . At what partial pressure of the gas the molality of aqueous solution will be $\frac{5}{9}m$ :

• A. $1.5atm$
• B. $3atm$
• C. $6atm$
• D. $9atm$

Answer 1

Answer: (B)

$P=K_{H}\left(\frac{n_{g}}{n_{g} + n_{l}}\right)$ but $n_{g} < < n_{1}P=K_{H}\left(\frac{n_{g}}{n_{l}}\right)$
$=K_{H}\left(\frac{m}{1000} \times M_{\text{solvent }}\right)$
$=3\times 10^{2}\times \frac{5}{9}\times \frac{1}{1000}\times 18=3atm$