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Q. The height of a mountain is $ H $ and the density of its rock is $ 3 \times 10^{3} kg/m^{-3} $ . If the elastic limit of the rock is $ 3 \times 10^{8} N/m^{-2} $ , find the height of the mountain

AMUAMU 2014Mechanical Properties of Solids

Solution:

Stress $=\frac{F}{A}$
$=\frac{mg}{A}=\frac{Vdg}{A}=\frac{AHdg}{A}=Hdg$
Elastic limit of the rock $=3\times 10^{8} N/m^{2}$
$3\times 10^{8}=Hdg$
$3 \times 10^{8}=H \times 3\times 10^{4}$
$\Rightarrow H=10\,km$