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Q. The height of a mercury barometer is $95 cm$ at sea level and $60 cm$ at the top of a hill. The ratio of density of mercury to that of air is $10^{4}$. The height of the hill is

Mechanical Properties of Fluids

Solution:

$\Delta h 'P _{ Hg } g = h \rho_{ air } g$
$h =\frac{\Delta h ' \rho_{ Hg } g }{\rho_{ ar } g }$
$=(95-60) 10^{-2} \times 10^{+4}$
$h =35 \times 10^{2}=3500 \approx 3 km$