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Q.
The height of a HCP unit cell is $5.715 \mathring{A}$. What is the volume of the unit cell in $ \mathring{A}^3$ ?
NTA AbhyasNTA Abhyas 2020The Solid State
Solution:
The height of the HCP unit cell
$=4 \sqrt{\frac{2}{3}} \cdot r=5.715 $
$r=\frac{5.715 \times \sqrt{3}}{\sqrt{2} \times 4}=1.75 \mathring{A}$
The base area of the unit cell
$=6 \sqrt{3} r ^2$
The volume of the unit cell
$=\text { base area } \times $
$\text { height }=24 \sqrt{2} r^3=181.8 \mathring{A}^3$