1. Tardigrade
  2. Question
  3. Chemistry
  4. The heat of solution of one mole of Na2SO4.10H2O is -78.7 kJ, and that of dehydration, -81.6 kJ. The heat of solution (kJ) of anhydrous sodium sulphate is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The heat of solution of one mole of $Na_{2}SO_{4}.10H_{2}O$ is -78.7 kJ, and that of dehydration, -81.6 kJ. The heat of solution (kJ) of anhydrous sodium sulphate is

NTA AbhyasNTA Abhyas 2020Thermodynamics

Solution:

Solution

From Hess's law, $\text{Q} = - \left(- 81.6 \, \text{kJ}\right) + \left(- 78.7 \, \text{kJ}\right)$

$= 81.6 \, \text{kJ} - 78.7 \, \text{kJ} = + 2.9 \, \text{kJ}$