Question

The heat of neutralisation of a strong acid and a strong alkali is $ 57.0 \,kJ\, mol^{-1} $ . The heat released when $ 0.5 $ mole of $ HNO_3 $ solution is mixed with $ 0:2 $ mole of $ KOH $ is

• A. $ 57.0 \,kJ $
• B. $ 11.4 \,kJ $
• C. $ 28.5\,kJ $
• D. $ 34.9 \,kJ $

Answer 1

Answer: (B)

$\because 0.2$ mole will neutralise 0.2 mole of $HNO _{3}$.

$\therefore $ Heat evolved $=57 \times 0.2$

$=11.4 kJ$