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  4. The heat generated in a circuit is given by Q = I 2 Rt, where I is current, R is resistance and t is time. If the percentage errors in measuring I , R and t are 2 %, 1 % and 1 % respectively, then the maximum error in measuring heat will be

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Q. The heat generated in a circuit is given by $Q = I ^{2} Rt$, where $I$ is current, $R$ is resistance and $t$ is time. If the percentage errors in measuring $I , R$ and $t$ are $2 \%, 1 \%$ and $1 \%$ respectively, then the maximum error in measuring heat will be

BITSATBITSAT 2020

Solution:

$\frac{\Delta Q}{Q} \times 100=\frac{2 \Delta I}{I} \times 100+\frac{\Delta R}{R} \times 100+\frac{\Delta t}{t} \times 100$
$=2 \times 2 \%+1 \%+1 \%=6 \%$