1. Tardigrade
  2. Question
  3. Chemistry
  4. The heat evolved in combustion of 112 L of water gas (mixture of equal volume of H 2( g ) and .CO ( g )) is H 2( g )+(1/2) O 2( g ) leftharpoons H 2 O ( g ) ; Δ H =-241.8 kJ CO ( g )+(1/2) O 2( g ) leftharpoons CO 2( g ) ; Δ H =-283 kJ

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Q. The heat evolved in combustion of $112\, L$ of water gas (mixture of equal volume of $H _{2}( g )$ and $\left.CO ( g )\right)$ is
$H _{2}( g )+\frac{1}{2} O _{2}( g ) \rightleftharpoons H _{2} O ( g ) ; \Delta H =-241.8\, kJ$
$CO ( g )+\frac{1}{2} O _{2}( g ) \rightleftharpoons CO _{2}( g ) ; \Delta H =-283 \,kJ$

Solution:

On adding both equations we get
$H _{2}+ CO + O _{2} \rightarrow H _{2} O + CO _{2} ; \Delta H =-524.8 \,kJ$
$2 \times 22.4$ litre $\left( H _{2}+ CO \right)$ evolve $524.8\, kJ$ heat
$\therefore 112\, L$ water gas evolved heat
$=\frac{524.8}{44.8} \times 112$
$=1312\, kJ$