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  4. The half life period of a radioactive substance is 60 days. The time taken for (7/8) th of its original mass to disintegrate will be :

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Q. The half life period of a radioactive substance is 60 days. The time taken for $\frac{7}{8}$ th of its original mass to disintegrate will be :

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Solution:

$7 / 8$ disintegrates means $1 / 8$ remains
Or $\left(\frac{1}{2}\right)^3 $
$ \therefore 3$ half lives
$ =180 $ days