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Chemistry
The half-life period of a order reaction is 60 minutes What percentage will be left over after 240 minutes ?
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Q. The half-life period of a order reaction is 60 minutes What percentage will be left over after 240 minutes ?
KCET
KCET 2016
Chemical Kinetics
A
$6.25\%$
53%
B
$4.25\%$
30%
C
$5\%$
10%
D
$6\%$
8%
Solution:
Given, $t_{1 / 2}=60$ min
Number of half-lives (n),
$T=n \times t_{1 / 2} $
$\therefore \, n=\frac{T}{t_{1 / 2}}=\frac{240}{60}=4$
Let the initial amount be 100
Then amount left (a-x) after four $(n=4)$
half-lives $= \frac{100}{2^{n}} $
$(a-x)=\frac{100}{c^{4}}=\frac{100}{16} $
$(a-x)=6.25 \%$