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  4. The half life of Pa218 is 3 minutes. What fraction of 10g sample of Pa218 will remain after 15 minutes ?

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Q. The half life of $Pa^{218}$ is 3 minutes. What fraction of 10g sample of $Pa^{218}$ will remain after 15 minutes ?

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Solution:

$\frac{N}{N_0} = \left( \frac{1}{2} \right)^{t/T} = \left( \frac{1}{2} \right)^{15/3} = \left( \frac{1}{2} \right)^5 = \frac{1}{32}$