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Chemistry
The half life of a first order reaction is 2000 years. If the concentration after 8000 years is 0.02 M, then the initial concentration was :
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Q. The half life of a first order reaction is $2000$ years. If the concentration after $8000$ years is $0.02\, M$, then the initial concentration was :
NEET
NEET 2022
Chemical Kinetics
A
$0.16 \,M$
20%
B
$0.32 \,M$
28%
C
$0.08 \, M$
33%
D
$0.04 \, M$
18%
Solution:
$k =\frac{2.303}{ t } \log \frac{[ A ]_0}{[ A ]_{ t }}$
$\frac{0.693}{2000}=\frac{2.303}{8000} \log \frac{[ A ]_0}{0.02}$
$\therefore[ A ]_0=0.32 \,M$