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Q. The half life of a certain first order reaction is 60 minutes. How long will it take for 80% reaction to occur ?

Chemical Kinetics

Solution:

$k=\frac{2.303}{t}log \left(\frac{a}{a-x}\right)$
$\frac{0.693}{60}=\frac{2.303}{t}log \left(\frac{100}{100-80}\right)$
$t=199.39\,min$