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Q. The [H+] of a resulting solution that is 0.01 M acetic acid (Ka = 1.8 x 10-5) and 0.01 M in benzoic acid (Ka = 6.3 x 10-5) is

NTA AbhyasNTA Abhyas 2022

Solution:

$\left[\text{H}^{+}\right] = \sqrt{\text{k}_{1} \text{C}_{1} + \text{k}_{2} \text{C}_{2}}$
(for mixture of two weak acids)
$= \sqrt{\text{1.8} \times 1 0^{- 5} \times \text{0.01} + \text{6.3} \times 1 0^{- 5} \times \text{0.01}}$
$= \sqrt{\text{18} \times 1 0^{- 8} + 6 3 \times 1 0^{- 8}}$
$= 9 \times 1 0^{- 4}$