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Q.
The $H_β$ line of hydrogen
Atoms
Solution:
The wavelength of $Hβ$ line is $486.1 \,nm.$
The wavelength of $H_β$ line is greater than that of $H_γ$ line $\left(\lambda_{H_γ}= 434.1\, nm\right).$
$H_β$ line corresponds to transition from the third excited state $(n = 4)$ to the first excited state $(n = 2)$.