1. Tardigrade
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  3. Chemistry
  4. The H - Cl bond length is 1.275 mathringA (charge e=4.8 × 10-10 esu). If μ=1.02 D , then HCl is

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Q. The $H - Cl$ bond length is $1.275 \mathring{A}$ (charge $e=4.8 \times 10^{-10}$ esu). If $\mu=1.02\, D ,$ then $HCl$ is

Chemical Bonding and Molecular Structure

Solution:

The percent ionic nature

$=\frac{\text { Observed } \mu}{\text { Theoretical } \mu} \times 100=\frac{1.02}{1.275 \times 4.8} \times 100$

$=17 \%$ ionic or $=83 \%$ covalent.