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Physics
The gravitational field intensity at a point 10,000 km from the centre of the earth is 4.8 N kg-1. The gravitational potential at that point is
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Q. The gravitational field intensity at a point $10,000 \,km$ from the centre of the earth is $4.8 \,N \,kg^{-1}$. The gravitational potential at that point is
Gravitation
A
$-4.8 \times 10^{-7} \,J \,kg^{-1}$
62%
B
$-2.4 \times 10^7 \,J \,k^{-1}$
8%
C
$4.8 \times 10^6 \,J \,kg^{-1}$
31%
D
$3.6 \times 10^6\, J \,kg^{-1}$
0%
Solution:
Gravitational field intensity, $E = \frac{GM}{R^2}$
Gravitational potential, $V = -\frac{GM}{R}$
$\therefore \frac{V}{E} =-R$
or $V = -ER $
$= - 4.8 \times 10.000\times \times 10^2$
$= -4.8 \times10^7\,J\,kg^{-1}$