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Q.
The graph that does not represent the behaviour of an ideal gas is
KVPYKVPY 2012
Solution:
$p V=n R T$
$p=\frac{R T}{V}($ for $1 $ mole $)$
At constant $T, p$ would be inversely proportional to $V$.
So, plot of $p$ versus $V$ would
Thus, plot (a) is correct.
According to ideal gas equation.
$p V=n R T $ or $\frac{p V}{T}=n R$
As $R$ is a gas constant, so plot between $p V$ versus $T$ would be linear and slope will be $n$. i.e.
Also, from ideal gas equation $p$ is directly proportional to $\frac{1}{V}$.
Therefore, plot between $p$ versus $\frac{1}{V}$ is a straight line, i.e.
Thus, plot (b) is incorrect.