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Q.
The graph of displacement versus time is shown. Its corresponding velocity-time graph will be
Motion in a Straight Line
Solution:
As slope of $s-t$ graph decreases with $t$, so $v-t$ will decrease. At the top of the graph slope is zero, so velocity is zero. In the downward journey slope of $s-t$ graph increases negatively. So velocity represented by it will be negative.
