Thank you for reporting, we will resolve it shortly
Q.
The graph In $K_{(eq.)vs} \frac{1}{T}$ relates for a reaction. The reaction must be:
Equilibrium
Solution:
$In \frac{K_{2}}{K_{1}} =\frac{\Delta H}{R}\left[\frac{T_{2}-T_{1}}{T_{1}T_{2}}\right]$
Since $K$ is increased or decreased with temperature, thus $\Delta H = -v e$
