Question

The graph between two temperature scales $P$ and $Q$ is shown in the figure. Between upper fixed point and lower fixed point there are $150$ equal divisions of scale $P$ and $100$ divisions on scale $Q$ : The relationship for conversion between the two scales is given by:-

• A. $\frac{t_P}{100}=\frac{t_Q-180}{150}$
• B. $\frac{t_Q}{150}=\frac{t_P-180}{100}$
• C. $\frac{t_p}{180}-\frac{t_Q-40}{100}$
• D. $\frac{t_Q}{100}=\frac{t_P-30}{150}$

Answer 1

Answer: (D)

$ \frac{\text { reading on scale }-\text { Lower fixed point }}{\text { upper fixed po int-lower fixed point }}=\text { constant }$
$ \frac{t_p-30}{180-30}=\frac{t_Q-0}{100-0} $
$ \frac{t_p-30}{150}=\frac{t_Q}{100}$