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  4. The given circle x2+y2+2 p x=0, p ∈ R touches the parabola y2=4 x externally, then

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Q. The given circle $x^2+y^2+2 p x=0, p \in R$ touches the parabola $y^2=4 x$ externally, then

Conic Sections

Solution:

$V=\left(a, \frac{a\left(1+t^2\right)}{t}\right)$ and $T: t y=x+a t^2$ put $x=a \& x=-a$
$U=\left(-a, \frac{a\left(t^2-1\right)}{t}\right)$

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