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  4. The geometry and the number of unpaired electron(s) of [MnBr4]2-, respectively, are

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Q. The geometry and the number of unpaired electron(s) of $[MnBr_{4}]^{2-}$, respectively, are

KVPYKVPY 2015Coordination Compounds

Solution:

The oxidation state of $Mn$ in $[MnBr_{4}]^{-2}$ is $+2$ .
The electronic configuration of $Mn^{2+}$ is $[Ar] \,3d_{5} 4s_{0}$
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As, $Br^{-}$ is a weak field ligand pairing of electron will not occur
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As, the hybridisation of $Mn$ in $[MnBr_{4}]^{2-}$ is $sp^3$, thus its geometry will be tetrahedral and it contains five unpaired electrons.