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Q. The geometrical arrangement of electron pairs and shape of $I_{3}^{-}$ are respectively

Chemical Bonding and Molecular Structure

Solution:

$X$ for $I_{3}^{-}=\frac{1}{2}[7+2-0+1]=5$ $X=$ Total no. of electron pairs around central atom Hybridisation of $I$ in $I_{3}^{-}$ is $s p^{3} d$. Thus $I_{3}^{-}$ has trigonal bipyramidal geometry with linear shape.