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Q.
The gas phase reaction $2 NO _{2}( g ) \rightarrow N _{2} O _{4}( g )$ is an
exothermic reaction. The decomposition of $N _{2} O _{4}$, in equilibrium mixture of $NO _{2}( g )$ and $N _{2} O _{4}( g )$, can be increased by
We have $2 NO _{2}( g ) \rightleftharpoons N _{2} O _{4}( g ) ; \Delta H=- ve$
On adding the inert gas, the number of moles per unit volume of various reactants and products will decrease.
Hence, the equilibrium will shift towards the direction in which there is increase in number of moles of gases.
Therefore, in above case, reaction will move towards backward direction which will lead to the decomposition of dinitrogen tetraoxide $\left( N _{2} O _{4}\right)$.