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Q. The gap between the plates of a parallel plate capacitor of area A and distance between plates $d$, is filled with a dielectric whose permittivity varies linearly from $\epsilon_{1}$ at one plate to $\epsilon_{2}$ at the other. The capacitance of capacitor is :

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Solution:

$\varepsilon=\left(\frac{\varepsilon_{2}-\varepsilon_{1}}{d}\right) x+\varepsilon_{1} $
$d C=\frac{\varepsilon_{0} \varepsilon A}{d x} $
$C_{\text {eq }}=\int dc$