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  4. The fringe width at a distance of 50 cm from the slits in Young's experiment for light of wavelength 6000 mathringA is 0.048 cm. The fringe width at the same distance for λ=5000 mathringA, will be

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Q. The fringe width at a distance of $50\, cm$ from the slits in Young's experiment for light of wavelength $6000\,\mathring{A}$ is $0.048\, cm$. The fringe width at the same distance for $\lambda=5000\,\mathring{A}$, will be

Wave Optics

Solution:

As, $\beta'=\frac{\lambda'}{\lambda} \beta=\frac{5000}{6000} \times 0.48=0.04\, cm$