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Q. The frictional force acting on $1\, kg$ block isPhysics Question Image

Laws of Motion

Solution:

If both move together $a=\frac{10}{101} \simeq 0.1\, m / s ^{2}$
Now,
$F_{\text {net }}=1(0.1)=0.1\, N$
$f_{L}=(0.5)(1)(g)=5\, N$
So, $f=0.1\, N$