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  4. The frequency of an alternating voltage is 50 cycles/sec and its amplitude is 120 V. Then the r.m.s. value of voltage is

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Q. The frequency of an alternating voltage is $50$ cycles/sec and its amplitude is $120\, V$. Then the r.m.s. value of voltage is

Alternating Current

Solution:

$V_{ rms }=\frac{V_{0}}{\sqrt{2}}$
$=\frac{120}{1.414}=84.8\, V$