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Q. The frequency of a light wave in a material is $ 2 \times {10}^{14} \,Hz$ and wavelength is $5000 \,\mathring{A}$. The refractive index of material will be

AIPMTAIPMT 2007

Solution:

Refractive index $\mu=\frac{ c }{ v }=\frac{ c }{ v \lambda} $
$ = \frac{3 \times 10^{8}}{2 \times 10^{14} \times 5000 \times 10^{-10}}=3 $