Q. The freezing point of equimolal aqueous solution will be highest for:
NTA AbhyasNTA Abhyas 2022
Solution:
$\Delta T_{f} \propto m\times i$
m = molality, i = Van't Hoff factor
Except glucose, all other electrolytes are undergoing dissociation so $\left(\right.i>1\left.\right)$ . Glucose is non electrolyte, $i=1$ . So, it has least value of $\Delta T_{f}$ hence, its freezing point is maximum.
m = molality, i = Van't Hoff factor
Except glucose, all other electrolytes are undergoing dissociation so $\left(\right.i>1\left.\right)$ . Glucose is non electrolyte, $i=1$ . So, it has least value of $\Delta T_{f}$ hence, its freezing point is maximum.