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Q. The freezing point of a solution composed of $10.0\, g$ of $KCl$ in $100 \,g$ of water is $4.5^{\circ}C$. Calculate the van't Hoff factor, $i$ for this solution.

VITEEEVITEEE 2011

Solution:

$\Delta T_{f} = iK_{f} m$
$m = \frac{10\times 1000}{74.55 \times100} = 1.34\,m$
[Molecular Mass of $KCl = 74.55$]
$i = \frac{\Delta T_{f}}{K_{f} m} = \frac{4.5^{\circ}}{\left(1.86^{\circ}C/m\right)\left(1.34m\right)} = 1.8$